50 Examples Of Balanced Chemical Equations With Answers

Introduction

Balancing chemical equations is a fundamental skill in chemistry that ensures the conservation of mass and atoms during a reaction. Also, this article presents 50 examples of balanced chemical equations with answers, covering a wide range of reaction types—from combustion and synthesis to decomposition and redox processes. In practice, whether you’re a high‑school student tackling stoichiometry problems or a chemistry enthusiast exploring reaction mechanisms, having a ready reference of balanced chemical equations can save time and reduce errors. Each example is written in a clear, step‑by‑step format to help you understand the logic behind the coefficients Worth keeping that in mind..

How to Balance a Chemical Equation

1. Write the skeleton equation with the correct formulas.
2. Count the atoms of each element on both sides.
3. Adjust coefficients (not subscripts) to equalize the atom counts.
4. Check your work to ensure all elements are balanced.
5. Simplify the coefficients to the smallest whole numbers.

Remember: subscripts cannot be changed; only coefficients can be altered.

50 Balanced Chemical Equations

14| ( \text{C}_2\text{H}_5\text{OH} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} ) | ( \text{C}_2\text{H}_5\text{OH} + 3,\text{O}_2 \rightarrow 2,\text{CO}_2 + 3,\text{H}_2\text{O})

15 | ( \text{Mg} + \text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2 ) | ( \text{Mg} + 2,\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2)

16 | ( \text{NaCl} + \text{AgNO}_3 \rightarrow \text{AgCl} + \text{NaNO}_3 ) | ( \text{NaCl} + \text{AgNO}_3 \rightarrow \text{AgCl} + \text{NaNO}_3) (already balanced)

17 | ( \text{Fe}_2\text{O}_3 + \text{CO} \rightarrow \text{Fe} + \text{CO}_2 ) | ( \text{Fe}_2\text{O}_3 + 3,\text{CO} \rightarrow 2,\text{Fe} + 3,\text{CO}_2)

The next setof reactions illustrates how the same systematic approach can be applied to a variety of chemical contexts, from simple synthesis to more complex redox transformations It's one of those things that adds up. Surprisingly effective..

18. ( \text{Na}_2\text{S}_2\text{O}_3 + \text{I}_2 \rightarrow \text{NaI} + \text{Na}_2\text{S}_4\text{O}_6 )
Balanced form: ( \text{Na}_2\text{S}_2\text{O}_3 + \text{I}_2 \rightarrow 2,\text{NaI} + \text{Na}_2\text{S}_4\text{O}_6 )

19. ( \text{C}_2\text{H}_6 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} )
Balanced form: ( \text{C}_2\text{H}_6 + \tfrac{7}{2},\text{O}_2 \rightarrow 2,\text{CO}_2 + 3,\text{H}_2\text{O} ) – multiplying by 2 to clear the fraction yields ( 2,\text{C}_2\text{H}_6 + 7,\text{O}_2 \rightarrow 4,\text{CO}_2 + 6,\text{H}_2\text{O} )

20. ( \text{Al} + \text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2 )
Balanced form: ( 2,\text{Al} + 6,\text{HCl} \rightarrow 2,\text{AlCl}_3 + 3,\text{H}_2 )

21. ( \text{KMnO}_4 + \text{H}_2\text{SO}_4 \rightarrow \text{KHSO}_4 + \text{MnSO}_4 + \text{CO}_2 + \text{H}_2\text{O} )
Balanced form: ( 2,\text{KMnO}_4 + 5,\text{H}_2\text{SO}_4 \rightarrow K_2\text{SO}_4 + 2,\text{MnSO}_4 + 5,\text{CO}_2 + 8,\text{H}_2\text{O} )

22. ( \text{Ca(OH)}_2 + \text{HCl} \rightarrow \text{CaCl}_2 + \text{H}_2\text{O} )
Balanced form: ( \text{Ca(OH)}_2 + 2,\text{HCl} \rightarrow \text{CaCl}_2 + 2,\text{H}_2\text{O} )

23. ( \text{Na}_3\text{PO}_4 + \text{HCl} \rightarrow \text{NaCl} + \text{H}_3\text{PO}_4 )
Balanced form: ( \text{Na}_3\text{PO}_4 + 3,\text{HCl} \rightarrow 3,\text{NaCl} + \text{H}_3\text{PO}_4 )

24. ( \text{BaCl}_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + \text{NaCl} )
Balanced form: ( \text{BaCl}_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2,\text{NaCl} )

Refining the Technique When tackling unfamiliar equations, a reliable workflow can streamline the process:

1. Catalogue each element present on both sides of the reaction.
2. Identify the species that appear only once on each side; these often dictate the initial coefficient choices.
3. Adjust coefficients systematically, starting with the most complex molecule, to satisfy the atom count for every element.
4. Simplify by reducing the set of coefficients